挺简单的，多占内存，少用循环

Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800x600), you are supposed to point out the strictly dominant color.

Input Specification:

Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (<=800) and N (<=600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0, 2²⁴). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.

Output Specification:

For each test case, simply print the dominant color in a line.

Sample Input:

5 30 0 255 16777215 2424 24 0 0 2424 0 24 24 24

Sample Output:

24

来源： <>

 

1. #pragma warning(disable:4996)
2. #include <stdio.h>
4. using namespace std;
5. int a[16777216];
6. int main(void) {
7. int m, n;
8. scanf("%d %d", &m, &n);
9. int p = m*n,temp,count=0,result=0;
10. for (int i = 0; i < p; i++) {
11. scanf("%d", &temp);
12. a[temp]++;
13. if (a[temp] > count) {
14. count = a[temp];
15. result = temp;
16. }
17. }
18. printf("%d", result);
21. return 0;
22. }